Trajectory Intersection In Python
Solution 1:
this is a bit broader topic so I will focus only on the math/physics part as I got the feeling the CV/DIP part is already handled by both of you askers (andre ahmed, and chris burgees).
For simplicity I am assuming linear movement with constant speeds So how to do this:
obtain 2D position of each object for 2 separate frames after known time
dt
so obtain the 2D center (or corner or whatever) position on the image for each object in question.
convert them to 3D
so using known camera parameters or known bacground info about the scene you can un-project the 2D position on screen into 3D relative position to camera. This will get rid of the non linear interpolations otherwise need if handled just like a 2D case.
There are more option how to obtain 3D position depending on what you got at your disposal. For example like this:
obtaining actual speed of objects
the speed vector is simply:
vel = ( pos(t+dt) - pos(t) )/dt
so simply subbstract positions of the same object from 2 consequent frames and divide by the framerate period (or interval between the frames used).
test each 2 objects for collision
this is the funny stuff Yes you can solve a system of inequalities like:
| ( pos0 + vel0 * t ) - (pos1 + vel1 * t ) | <= threshold
but there is a simpler way I used in here
The idea is to compute
t
where the tested objects are closest together (if nearing towards eachother).so we can extrapolate the future position of each object like this:
pos(t) = pos(t0) + vel*(t-t0)
where
t
is actual time andt0
is some start time (for examplet0=0
).let assume we have 2 objects (
pos0,vel0,pos1,vel1
) we want to test so compute first 2 iterations of their distance so:pos0(0) = pos0; pos1(0) = pos1; dis0 = | pos1(0) - pos0(0) | pos0(dt) = pos0 + vel0*dt; pos1(dt) = pos1 + vel1*dt; dis1 = | pos1(dt) - pos0(dt) |
where
dt
is some small enough time (to avoid skipping through collision). Nowif (dis0<dis1)
then the objects are mowing away so no collision,if (dis0==dis1)
the objects are not moving or moving parallel to each and onlyif (dis0>dis1)
the objects are nearing to each other so we can estimate:dis(t) = dis0 + (dis1-dis0)*t
and the collision expects that
dis(t)=0
so we can extrapolate again:0 = dis0 + (dis1-dis0)*t (dis0-dis1)*t = dis0t= dis0 / (dis0-dis1)
where
t
is the estimated time of collision. Of coarse all this handles all the movement as linear and extrapolates a lot so its not accurate but as you can do this for more consequent frames and the result will be more accurate with the time nearing to collision ... Also to be sure you should extrapolate the position of each object at the time of estimated collision to verify the result (if not colliding then the extrapolation was just numerical and the objects did not collide just was nearing to each for a time)
As mentioned before the conversion to 3D (bullet #2) is not necessary but it get rid of the nonlinearities so simple linear interpolation/extrapolation can be used later on greatly simplify things.
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