How To Parse The Iso Format Datetime String In Python?

In pandas how can we make the datetime column from this data? df = pd.DataFrame({'date': ['2020-02-04T22:03:44.846000+00:00']}) print(df) date 0 20

Solution 1:

Thanks to @Felipe,

I got the answer.

df['date'] = pd.to_datetime(df['date'],infer_datetime_format=True)

df = pd.DataFrame({'date': ['2020-02-04T22:03:44.846000+00:00']})

df['year'] = df['date'].dt.year
print(df)

                              date  year
02020-02-04 22:03:44.846000+00:002020

Solution 2:

You can parse date time string format using this reference: https://docs.python.org/3/library/datetime.html#strftime-and-strptime-behavior

import numpy as np
import pandas as pd

pd.options.display.max_columns = 10
pd.set_option('display.max_colwidth', -1)

df = pd.DataFrame({'date': ['2020-02-04T22:03:44.846000+00:00']})

df['date1'] = pd.to_datetime(df['date'],format='%Y-%m-%dT%H:%M:%S.%f%z')
df['date2'] = pd.to_datetime(df['date'],infer_datetime_format=True)
df['hour'] = df['date1'].dt.hour

print(df)

02020-02-04T22:03:44.846000+00:002020-02-04 22:03:44.846000+00:00   

                             date2  hour  
02020-02-04 22:03:44.846000+00:0022