Pandas: Subtracting Current Date From The Date In A Pandas Table
Solution 1:
You have to subtract same types - datetimes with datetime (with zero times) or dates with date.
Use Timestamp.now
with Timestamp.normalize
or Timestamp.floor
for remove time
s:
df['diff'] = pd.to_datetime( df['date']) - pd.Timestamp.now().normalize()
df['diff'] = pd.to_datetime( df['date']) - pd.Timestamp.now().floor('d')
You can also use replace
:
dt = pd.datetime.now().replace(hour=0, minute=0, second=0, microsecond=0)
df['diff'] = pd.to_datetime( df['date']) - dt
Or convert Datetimes
to date
s for subtract same types:
dt = datetime.datetime.now().date()
df['diff'] = pd.to_datetime(df['date']).dt.date - dt
Sample:
rng = pd.date_range('2018-04-03', periods=10, freq='100D')
df = pd.DataFrame({'date': rng})
df['diff'] = pd.to_datetime( df['date']) - pd.Timestamp.now().normalize()
print (df)
date diff
0 2018-04-03 -261 days
1 2018-07-12 -161 days
2 2018-10-20 -61 days
3 2019-01-28 39 days
4 2019-05-08 139 days
5 2019-08-16 239 days
6 2019-11-24 339 days
7 2020-03-03 439 days
8 2020-06-11 539 days
9 2020-09-19 639 days
Solution 2:
There is a subtle but important distinction. Pandas supports datetime.datetime
objects but does not support datetime.date
objects:
from datetime import date, datetime
# TypeError: unsupported operand type(s) for -: 'DatetimeIndex' and 'datetime.date'
df['date'] - date.today()
# works correctly
df['date'] - datetime.now()
# works correctly
df['date'] - datetime.now().replace(minute=0, hour=0, second=0, microsecond=0)
Note pd.Timestamp.date
returns a datetime.date
object. The docs do specify this: Return date object with same year, month and day
. That date
object is not supported natively by Pandas in the same way datetime
objects are supported.
But replacing time values is cumbersome. You will likely prefer using in-built Pandas methods for your calculations. These are all equivalent:
df['date'] - pd.Timestamp('today').floor('D')
df['date'] - pd.Timestamp.today().normalize()
df['date'] - pd.to_datetime('today').normalize()
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